Integrand size = 21, antiderivative size = 100 \[ \int \frac {\sin ^2(a+b x)}{(d \cos (a+b x))^{7/2}} \, dx=\frac {4 \sqrt {d \cos (a+b x)} E\left (\left .\frac {1}{2} (a+b x)\right |2\right )}{5 b d^4 \sqrt {\cos (a+b x)}}+\frac {2 \sin (a+b x)}{5 b d (d \cos (a+b x))^{5/2}}-\frac {4 \sin (a+b x)}{5 b d^3 \sqrt {d \cos (a+b x)}} \]
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Time = 0.06 (sec) , antiderivative size = 100, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {2646, 2716, 2721, 2719} \[ \int \frac {\sin ^2(a+b x)}{(d \cos (a+b x))^{7/2}} \, dx=\frac {4 E\left (\left .\frac {1}{2} (a+b x)\right |2\right ) \sqrt {d \cos (a+b x)}}{5 b d^4 \sqrt {\cos (a+b x)}}-\frac {4 \sin (a+b x)}{5 b d^3 \sqrt {d \cos (a+b x)}}+\frac {2 \sin (a+b x)}{5 b d (d \cos (a+b x))^{5/2}} \]
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Rule 2646
Rule 2716
Rule 2719
Rule 2721
Rubi steps \begin{align*} \text {integral}& = \frac {2 \sin (a+b x)}{5 b d (d \cos (a+b x))^{5/2}}-\frac {2 \int \frac {1}{(d \cos (a+b x))^{3/2}} \, dx}{5 d^2} \\ & = \frac {2 \sin (a+b x)}{5 b d (d \cos (a+b x))^{5/2}}-\frac {4 \sin (a+b x)}{5 b d^3 \sqrt {d \cos (a+b x)}}+\frac {2 \int \sqrt {d \cos (a+b x)} \, dx}{5 d^4} \\ & = \frac {2 \sin (a+b x)}{5 b d (d \cos (a+b x))^{5/2}}-\frac {4 \sin (a+b x)}{5 b d^3 \sqrt {d \cos (a+b x)}}+\frac {\left (2 \sqrt {d \cos (a+b x)}\right ) \int \sqrt {\cos (a+b x)} \, dx}{5 d^4 \sqrt {\cos (a+b x)}} \\ & = \frac {4 \sqrt {d \cos (a+b x)} E\left (\left .\frac {1}{2} (a+b x)\right |2\right )}{5 b d^4 \sqrt {\cos (a+b x)}}+\frac {2 \sin (a+b x)}{5 b d (d \cos (a+b x))^{5/2}}-\frac {4 \sin (a+b x)}{5 b d^3 \sqrt {d \cos (a+b x)}} \\ \end{align*}
Result contains higher order function than in optimal. Order 5 vs. order 4 in optimal.
Time = 0.05 (sec) , antiderivative size = 59, normalized size of antiderivative = 0.59 \[ \int \frac {\sin ^2(a+b x)}{(d \cos (a+b x))^{7/2}} \, dx=\frac {\sqrt [4]{\cos ^2(a+b x)} \operatorname {Hypergeometric2F1}\left (\frac {3}{2},\frac {9}{4},\frac {5}{2},\sin ^2(a+b x)\right ) \sin ^3(2 (a+b x))}{24 b (d \cos (a+b x))^{7/2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(364\) vs. \(2(112)=224\).
Time = 1.03 (sec) , antiderivative size = 365, normalized size of antiderivative = 3.65
method | result | size |
default | \(\frac {4 \sqrt {d \left (2 \left (\cos ^{2}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )-1\right ) \left (\sin ^{2}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )}\, \left (8 \left (\sin ^{6}\left (\frac {b x}{2}+\frac {a}{2}\right )\right ) \cos \left (\frac {b x}{2}+\frac {a}{2}\right )-4 \sqrt {2 \left (\sin ^{2}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )-1}\, E\left (\cos \left (\frac {b x}{2}+\frac {a}{2}\right ), \sqrt {2}\right ) \sqrt {\frac {1}{2}-\frac {\cos \left (b x +a \right )}{2}}\, \left (\sin ^{4}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )-8 \cos \left (\frac {b x}{2}+\frac {a}{2}\right ) \left (\sin ^{4}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )+4 \sqrt {2 \left (\sin ^{2}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )-1}\, E\left (\cos \left (\frac {b x}{2}+\frac {a}{2}\right ), \sqrt {2}\right ) \sqrt {\frac {1}{2}-\frac {\cos \left (b x +a \right )}{2}}\, \left (\sin ^{2}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )+\left (\sin ^{2}\left (\frac {b x}{2}+\frac {a}{2}\right )\right ) \cos \left (\frac {b x}{2}+\frac {a}{2}\right )-\sqrt {\frac {1}{2}-\frac {\cos \left (b x +a \right )}{2}}\, \sqrt {2 \left (\sin ^{2}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )-1}\, E\left (\cos \left (\frac {b x}{2}+\frac {a}{2}\right ), \sqrt {2}\right )\right ) \sqrt {-2 \left (\sin ^{4}\left (\frac {b x}{2}+\frac {a}{2}\right )\right ) d +d \left (\sin ^{2}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )}}{5 d^{4} \sin \left (\frac {b x}{2}+\frac {a}{2}\right )^{3} \left (8 \left (\sin ^{6}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )-12 \left (\sin ^{4}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )+6 \left (\sin ^{2}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )-1\right ) \sqrt {d \left (2 \left (\cos ^{2}\left (\frac {b x}{2}+\frac {a}{2}\right )\right )-1\right )}\, b}\) | \(365\) |
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 0.10 (sec) , antiderivative size = 120, normalized size of antiderivative = 1.20 \[ \int \frac {\sin ^2(a+b x)}{(d \cos (a+b x))^{7/2}} \, dx=-\frac {2 \, {\left (-i \, \sqrt {2} \sqrt {d} \cos \left (b x + a\right )^{3} {\rm weierstrassZeta}\left (-4, 0, {\rm weierstrassPInverse}\left (-4, 0, \cos \left (b x + a\right ) + i \, \sin \left (b x + a\right )\right )\right ) + i \, \sqrt {2} \sqrt {d} \cos \left (b x + a\right )^{3} {\rm weierstrassZeta}\left (-4, 0, {\rm weierstrassPInverse}\left (-4, 0, \cos \left (b x + a\right ) - i \, \sin \left (b x + a\right )\right )\right ) + \sqrt {d \cos \left (b x + a\right )} {\left (2 \, \cos \left (b x + a\right )^{2} - 1\right )} \sin \left (b x + a\right )\right )}}{5 \, b d^{4} \cos \left (b x + a\right )^{3}} \]
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Timed out. \[ \int \frac {\sin ^2(a+b x)}{(d \cos (a+b x))^{7/2}} \, dx=\text {Timed out} \]
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\[ \int \frac {\sin ^2(a+b x)}{(d \cos (a+b x))^{7/2}} \, dx=\int { \frac {\sin \left (b x + a\right )^{2}}{\left (d \cos \left (b x + a\right )\right )^{\frac {7}{2}}} \,d x } \]
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\[ \int \frac {\sin ^2(a+b x)}{(d \cos (a+b x))^{7/2}} \, dx=\int { \frac {\sin \left (b x + a\right )^{2}}{\left (d \cos \left (b x + a\right )\right )^{\frac {7}{2}}} \,d x } \]
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Timed out. \[ \int \frac {\sin ^2(a+b x)}{(d \cos (a+b x))^{7/2}} \, dx=\int \frac {{\sin \left (a+b\,x\right )}^2}{{\left (d\,\cos \left (a+b\,x\right )\right )}^{7/2}} \,d x \]
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